1990 United States Senate election in Rhode Island

1990 United States Senate election in Rhode Island

← 1984 November 6, 1990 1996 →
  Claiborne Pell.jpg Schneiderclaudine.jpg
Nominee Claiborne Pell Claudine Schneider
Party Democratic Republican
Popular vote 225,105 138,947
Percentage 61.8% 38.2%

Rhode Island Senate Election Results by County, 1990.svg
County results
Pell:      50–60%      60–70%

U.S. senator before election

Claiborne Pell

Elected U.S. Senator

Claiborne Pell

The 1990 Rhode Island United States Senate election was held on November 6, 1990 to select the U.S. Senator from the state of Rhode Island. Democratic U.S. Senator Claiborne Pell decided to seek re-election and defeated Republican Representative Claudine Schneider in a landslide.[1]





United States Senate election in Rhode Island, 1990[2]
Party Candidate Votes % ±
Democratic Claiborne Pell (Incumbent) 225,105 61.83% -10.83%
Republican Claudine Schneider 138,947 38.17% +10.83%
Majority 86,158 23.67% -21.65%
Turnout 364,062
Democratic hold Swing

See also[edit]