1912 United States presidential election in Maryland

United States presidential election in Maryland, 1912

← 1908 November 5, 1912 1916 →
  Woodrow Wilson-H&E.jpg Theodore Roosevelt-Pach.jpg William Howard Taft - Harris and Ewing.jpg
Nominee Woodrow Wilson Theodore Roosevelt William Howard Taft
Party Democratic Progressive Republican
Home state New Jersey New York Ohio
Running mate Thomas R. Marshall Hiram Johnson Nicholas M. Butler
(replacing James S. Sherman)
Electoral vote 8 0 0
Popular vote 112,674 57,789 54,956
Percentage 48.57% 24.91% 23.69%

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

The 1912 United States presidential election in Maryland took place on November 5, 1912, as part of the 1912 United States presidential election. Maryland voters chose eight representatives, or electors, to the Electoral College, who voted for president and vice president.

Maryland was won by Princeton University President Woodrow Wilson (DVirginia), running with governor of Indiana Thomas R. Marshall, with 48.57% of the popular vote, against the 26th president of the United States Theodore Roosevelt (PNew York), running with governor of California Hiram Johnson, with 24.91% of the popular vote and the 27th president of the United States William Howard Taft (ROhio), running with Columbia University President Nicholas Murray Butler, with 23.69% of the popular vote.[1] As of the 2016 presidential election, this is the last time that Garrett County did not support the Republican candidate.

This was the first time since 1892 that a Democrat won the popular vote in Maryland.

Results[edit]

United States presidential election in Maryland, 1912[1]
Party Candidate Votes %
Democratic Woodrow Wilson 112,674 48.57%
Progressive Theodore Roosevelt 57,789 24.91%
Republican William Howard Taft 54,956 23.69%
Socialist Eugene V. Debs 3,996 1.72%
Prohibition Stuart Hamblen 2,244 0.97%
Socialist Labor Arthur Reimer 322 0.14%
Total votes 231,981 100%

References[edit]