1828 United States presidential election in Massachusetts

1828 United States presidential election in Massachusetts

← 1824 October 31 – December 2, 1828 1832 →
Turnout25.7%[1] Decrease 3.3 pp
  JohnQAdams.jpg Andrew Jackson.jpg
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 15 0
Popular vote 29,836 6,012
Percentage 76.36% 15.39%

The 1828 United States presidential election in Massachusetts took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Massachusetts voted for the National Republican candidate, incumbent president John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Massachusetts by a margin of 60.97%.

With 76.36% of the popular vote, Adams' home state would prove to be his second strongest victory in the 1828 election after neighboring Rhode Island.[2]

Results[edit]

1828 United States presidential election in Massachusetts[3]
Party Candidate Votes Percentage Electoral votes
National Republican John Quincy Adams 29,836 76.36% 15
Democratic Andrew Jackson 6,012 15.39% 0
N/A Other 3,226 8.26% 0
Totals 39,074 100.0% 15

References[edit]

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "1828 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  3. ^ "1828 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 28 February 2013.